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In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 11 feet long? x (to the nearest tenth) =

Respuesta :

calculista
the complete question in the attached figure

we know that
if the weights are perfectly balanced
40*(x)=50*(11-x)
40x=550-50x------------> 50x+40x=550--------------> x=6.11

x=6.1 ft

the answer is 6.1 ft
Ver imagen calculista

Answer:

[tex]x=6.11  feet[/tex]

Step-by-step explanation:

Given that in a fulcrum weights are perfectly balanced.

One side 40 lb weight is there and another side 50 lb weight is given

Let x be the length of 40 lb weight from fulcrum.  Then 50 lbs is at a distance of 11-x.

Then we have since weights are perfectly balanced

[tex]40x = 50(11-x)\\90x=550\\x=6.111[/tex]

Thus we get [tex]x=6.11[/tex]feet