A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of the air in the jar, causing the balloon to expand to a volume of 2.25 l. assuming a constant temperature, what is the new pressure inside the jar?
The first thing you should know in this case is the following definition: PV = nRT Then, as the temperature is constant, then: PV = k Then, we have two states: P1V1 = k P2V2 = k We can then equalize both equations: P1V1 = P2V2 Substituting the values: (1.25) * (101) = (2.25) * (P2) Clearing P2: P2 = ((1.25) * (101)) /(2.25)=56.11Kpa answer: the new pressure inside the jar is 56.11Kpa
