Respuesta :

LammettHash
Going out on a limb here and guessing that the function is

[tex]f(x)=8x^2\tan^{-1}(7x^3)[/tex]

Please correct me if this isn't the case.

Recall that

[tex]\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}[/tex]

which converges for [tex]|x|<1[/tex].

It follows that

[tex]8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}[/tex]
[tex]=\displaystyle\sum_{n\ge0}\frac{56(-49)^nx^{6n+3}}{2n+1}[/tex]

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